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2008-04-01 Seminar

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< Given a commutative semigroup with the neutral element and the cancellation law $$(S,+)$$, denote by $$\tilde{S}$$ the set $$S^{2}$$ with the equivalence relation $$R$$ such that $$(a,b)R(c,d)$$ if and only if $$a+d=b+c$$. We will show that under some assumptions it is possible to decompose $$\tilde{S}$$ into a direct sum of two subgroups: symmetric and asymmetric one.

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> Given a commutative semigroup with the neutral element and the cancellation law $$(S,+)$$, denote by $$\tilde{S}$$ the set $$S^{2}$$ with the equivalence relation $$R$$ such that $$(a,b)R(c,d)$$ if and only if $$a+d=b+c$$. We will show that $$(\tilde{S},+)$$ is a group and under some assumptions it is possible to decompose $$\tilde{S}$$ into a direct sum of two subgroups: symmetric and asymmetric one.


Hubert Przybycień

On a direct sum decomposition of a group $$ \tilde{S} $$

Given a commutative semigroup with the neutral element and the cancellation law $$ (S,+) $$, denote by $$ \tilde{S} $$ the set $$ S^{2} $$ with the equivalence relation $$ R $$ such that $$ (a,b)R(c,d) $$ if and only if $$ a+d=b+c $$. We will show that $$ (\tilde{S},+) $$ is a group and under some assumptions it is possible to decompose $$ \tilde{S} $$ into a direct sum of two subgroups: symmetric and asymmetric one.

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